lorddax wrote:... I was wondering if anyone has ever figured out how the HQ dice match up to standard dice, particularly into an easily findable Chessex set for those looking to play some HQ from all the printed materials but don't have the dice; d4, d6, d8, d10, d12, d20 and a d10 percentile.
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Well, I am not a mathematician and my English are bad, but it is all about possibilities. I’ve tried to remember some... (I believe I don’t have make mistake...)
At the two first examples I am trying to be more detailed but the third is more difficult.
2d6 for Attack 2= 1d4 where 1 is no skull, 2-3 is one skull, and 4 is two skullsthere are two dices, if the skull is true and the shield is false the possiblilities are the following:
True True
True False
False True
False False
True is 3 skulls per 6 sides= 3/6
False is 3 shiels per 6 sides = 3/6
True True = 3/6 x 3/6 = 9/36
True False = 3/6 x 3/6 = 9/36
False True = 3/6 x 3/6 = 9/36
False False = 3/6 x 3/6 = 9/36
so, two skulls are (True True) = 9/36 = 1/4
one True is (True False) + (False True) = 9/36 + 9/36 = 18/36 = 2/4
none True is (False False) = 9/36 = 1/4
for more complex calculation...
2d6 for Defence 2= 1d10 where 1 is reroll, 2-5 no white shield, 6-9 is one white shield, and 10 is two white shieldsthere are two dices, if the white shield is true and all the other values are false the possiblilities are the following:
True True
True False
False True
False False
True is 2 white shields per 6 sides= 2/6
False is 4 per 6 sides = 4/6
True True = 2/6 x 2/6 = 4/36
True False = 2/6 x 4/6 = 8/36
False True = 4/6 x 2/6 = 8/36
False False = 4/6 x 4/6 = 16/36
so, two white shields are (True True) = 4/36 = 1/9
one white shield is (True False) + (False True) = 8/36 + 8/36 = 16/36 = 4/9
no white shields is (False False) = 16/36 = 4/9
for a very complexed calculation...
4d6 for Defence 4= 1d100 where 1-19= reroll, 20-35= no shield, 36-67= 1 shield, 68-91 = 2 shields, 92-99 = 3 shield, 100= 4 shieldsTrue is 2 white shields per 6 sides= 2/6
False is 4 per 6 sides = 4/6
four white shields is 2/6 x 2/6 x 2/6 x 2/6 = (2/6)^4 = 16/1296
three white shields is 2/6 x 2/6 x 2/6 x 4/6 = (2/6)^3 x 4/6= 8/216 x 4/6 = 32/1296
two white shields is 2/6 x 2/6 x 4/6 x 4/6 = (2/6)^2 x (4/6)^2 = 4/36 x 16/36 = 64/1296
one white shields is 2/6 x 4/6 x 4/6 x 4/6 = 2/6 x (4/6)^3 = 2/6 x 64/216 = 128/1296
no white shields is 4/6 x 4/6 x 4/6 x 4/6 = (4/6)^4 = 256/1296
four shileds is 16/1296 = 1/81
three shileds (the false can be in four differend ways, T T T F, T T F T, T F T T, F T T T) (32/1296) x 4 = 128/1296 = 8/81
two shileds (the false can be in six differend ways*) (64/1296) x 6 = 384/1296 = 24/81
one shiled (the true can be in four differend ways) (128/1296) x 4 = 512/1296 = 32/81
no shield is 256/1296 = 16/81
*two shields in four dices, can have six differend compilations... F F T T, F T F T, etc...
it is like we have two "F" tring to take one of four possisions
the first "F" will take 1 to 4
the second "F" has one spot less because the first took it... so, it is 1 to 3
it is as we say two "F" where the first has 4 possibilities and the second 3... it is 4/2 x 3/2 = 12/2 = 6